**Single column**: SELECT col, COUNT(*) FROM t GROUP BY col HAVING COUNT(*) > 1. **Two columns**: GROUP BY col1, col2 HAVING COUNT(*) > 1. **Full rows**: SELECT * FROM t WHERE (col1, col2) IN (SELECT col1, col2 FROM t GROUP BY col1, col2 HAVING COUNT(*)>1). **Dedup strategy**: ROW_NUMBER() OVER (PARTITION BY key ORDER BY ts DESC) to keep first/last....
The complete answer continues with detailed implementation patterns, architectural trade-offs, and production-grade considerations. It covers performance optimization strategies, common pitfalls to avoid, and real-world examples from companies like Fossil Group. The answer also includes follow-up discussion points that interviewers commonly explore.
Continue Reading the Full Answer
Unlock the complete expert answer with code examples, trade-offs, and pro tips - plus 1,863+ more.
Or upgrade to Platform Pro - $39
Engineers who used these answers got offers at
AmazonDatabricksSnowflakeGoogleMeta
According to DataEngPrep.tech, this is one of the most frequently asked SQL interview questions, reported at 1 company. DataEngPrep.tech maintains a curated database of 1,863+ real data engineering interview questions across 7 categories, verified by industry professionals.