**Architectural Logic**: 1. Identify: GROUP BY key HAVING COUNT(*) > 1. 2. Resolve: ROW_NUMBER() OVER (PARTITION BY key ORDER BY tiebreaker) then keep rn=1. 3. Prevent: UNIQUE constraint, PK; MERGE/INSERT with conflict handling. **Why**: Duplicates indicate ingestion bug,...
This medium-level SQL question appears frequently in data engineering interviews at companies like Aarete, Dunnhumby, Incedo. While less common, it tests deeper understanding that distinguishes strong candidates. Mastering the underlying concepts (partition, sql) will help you answer variations of this question confidently.
Break this problem into components. Identify the core trade-offs involved, then walk the interviewer through your reasoning step by step. Demonstrate awareness of edge cases and production considerations - this is what separates good answers from great ones.
Architectural Logic: 1. Identify: GROUP BY key HAVING COUNT() > 1. 2. Resolve: ROW_NUMBER() OVER (PARTITION BY key ORDER BY tiebreaker) then keep rn=1. 3. Prevent: UNIQUE constraint, PK; MERGE/INSERT with conflict handling. Why: Duplicates indicate ingestion bug, missing idempotency, or intentional multi-version (e.g., SCD2). Fix root cause before ad-hoc dedup. Scalability: DELETE from CTE/subquery can lock; prefer INSERT INTO new_table SELECT ... WHERE rn=1 then swap, or use MERGE. Cost: Full scan + sort for ROW_NUMBER; DELETE is row-by-row logged. Example: WITH cte AS (SELECT , ROW_NUMBER() OVER (PARTITION BY key ORDER BY updated_at DESC) rn FROM t) DELETE FROM t WHERE (key, id) IN (SELECT key, id FROM cte WHERE rn > 1)βor use INSERT-overwrite pattern.
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Analyze My Answer β FreeAccording to DataEngPrep.tech, this is one of the most frequently asked SQL interview questions, reported at 3 companies. DataEngPrep.tech maintains a curated database of 1,863+ real data engineering interview questions across 7 categories, verified by industry professionals.