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Implement a query to find the top 5 customers by total sales amount.

SQLmedium0.5 min read

Reviewed by Aditya Kumar Β· Last reviewed 2026-03-24

**Architectural Logic**: Two approaches. 1. GROUP BY + ORDER BY + LIMIT: SELECT customer_id, SUM(sales_amount) total_sales FROM sales GROUP BY customer_id ORDER BY total_sales DESC LIMIT 5. 2. Window: SELECT * FROM (SELECT customer_id, SUM(sales_amount) total_sales, RANK() OVER...

πŸ€– Analyze Your Answer
Frequency
Low
Asked at 3 companies
Category
487
questions in SQL
Difficulty Split
130E|271M|86H
in this category
Total Bank
1,863
across 7 categories
Part of the SQL Window Functions Interview Preparation Hub
Explore SQL Window Functions Hub→
Reported in Interview Loops AtClick to view company-specific questions
🏒 Daniel Wellington Interview Hubβ†’πŸ’ Goldman Sachs Interview Hubβ†’πŸ’ Swiggy Interview Hubβ†’
Key Concepts Tested
partitionwindow

Why This Question Matters

This medium-level SQL question appears frequently in data engineering interviews at companies like Daniel Wellington, Goldman Sachs, Swiggy. While less common, it tests deeper understanding that distinguishes strong candidates. Mastering the underlying concepts (partition, window) will help you answer variations of this question confidently.

How to Approach This

Break this problem into components. Identify the core trade-offs involved, then walk the interviewer through your reasoning step by step. Demonstrate awareness of edge cases and production considerations - this is what separates good answers from great ones.

Expert Answer
105 words

Architectural Logic: Two approaches. 1. GROUP BY + ORDER BY + LIMIT: SELECT customer_id, SUM(sales_amount) total_sales FROM sales GROUP BY customer_id ORDER BY total_sales DESC LIMIT 5. 2. Window: SELECT * FROM (SELECT customer_id, SUM(sales_amount) total_sales, RANK() OVER (ORDER BY SUM(sales_amount) DESC) rk FROM sales GROUP BY customer_id) t WHERE rk <= 5. Why: LIMIT is simpler, stops early in some engines. RANK handles ties (multiple customers with same total); DENSE_RANK if ties should share rank. Scalability: Both require full aggregation; no early termination. Partition pruning on sales (e.g., by date) reduces input. Cost: Window adds sort overhead; for strict top 5, LIMIT is cheaper.

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Pro Tip

Red Flag: Using LIMIT 5 when business expects 'top 5 including ties'β€”inconsistent. Pro-Move: 'I confirm with product: strict 5 or include ties? RANK for leaderboard semantics.'

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