SELECT id FROM (SELECT id, COUNT(*) AS cnt FROM table GROUP BY id HAVING COUNT(*) > 200) t. If "more than 1 and greater than 200" means count > 200, HAVING COUNT(*) > 200 suffices (implies >1). **Why**: HAVING for aggregate filter....
This easy-level SQL question appears frequently in data engineering interviews at companies like Dunnhumby. While less common, it tests deeper understanding that distinguishes strong candidates. Mastering the underlying concepts (sql) will help you answer variations of this question confidently.
Start by clearly defining the core concept being asked about. Interviewers want to see that you understand the fundamentals before diving into implementation details. Structure your answer with a definition, then explain the practical application with a concise example.
SELECT id FROM (SELECT id, COUNT() AS cnt FROM table GROUP BY id HAVING COUNT() > 200) t. If "more than 1 and greater than 200" means count > 200, HAVING COUNT(*) > 200 suffices (implies >1). Why: HAVING for aggregate filter. Scalability: Large distinct counts—consider approximate (HyperLogLog) if exact not required.
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Analyze My Answer — FreeAccording to DataEngPrep.tech, this is one of the most frequently asked SQL interview questions, reported at 1 company. DataEngPrep.tech maintains a curated database of 1,863+ real data engineering interview questions across 7 categories, verified by industry professionals.