SELECT dish_id, dish_name, COUNT(*) AS order_count FROM orders o JOIN order_items oi ON o.order_id = oi.order_id WHERE order_date >= CURRENT_DATE - 30 GROUP BY dish_id, dish_name ORDER BY order_count DESC LIMIT 5. **Why**: Simple aggregation with date filter. Adjust schema per...
This medium-level SQL question appears frequently in data engineering interviews at companies like Swiggy. While less common, it tests deeper understanding that distinguishes strong candidates. Mastering the underlying concepts (join, sql) will help you answer variations of this question confidently.
Break this problem into components. Identify the core trade-offs involved, then walk the interviewer through your reasoning step by step. Demonstrate awareness of edge cases and production considerations - this is what separates good answers from great ones.
SELECT dish_id, dish_name, COUNT(*) AS order_count FROM orders o JOIN order_items oi ON o.order_id = oi.order_id WHERE order_date >= CURRENT_DATE - 30 GROUP BY dish_id, dish_name ORDER BY order_count DESC LIMIT 5. Why: Simple aggregation with date filter. Adjust schema per actual tables. Business: High-value for menu and inventory.
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Analyze My Answer — FreeAccording to DataEngPrep.tech, this is one of the most frequently asked SQL interview questions, reported at 1 company. DataEngPrep.tech maintains a curated database of 1,863+ real data engineering interview questions across 7 categories, verified by industry professionals.