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Check for duplicates in a table.

SQLmedium0.3 min read

Reviewed by Aditya Kumar Β· Last reviewed 2026-03-24

**Group by business key, HAVING COUNT(*) > 1.** Full duplicate rows: ROW_NUMBER() OVER (PARTITION BY col1, col2) and filter rn > 1. SELECT col1, col2, COUNT(*) FROM t GROUP BY col1, col2 HAVING COUNT(*) > 1; SELECT * FROM (SELECT *, ROW_NUMBER() OVER (PARTITION BY col1, col2...

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Frequency
Low
Asked at 1 company
Category
487
questions in SQL
Difficulty Split
130E|271M|86H
in this category
Total Bank
1,863
across 7 categories
Part of the SQL Query Optimization & Indexing Interview Preparation Hub
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Key Concepts Tested
partition
Expert Answer
57 words

Group by business key, HAVING COUNT(*) > 1. Full duplicate rows: ROW_NUMBER() OVER (PARTITION BY col1, col2) and filter rn > 1.

SELECT col1, col2, COUNT() FROM t GROUP BY col1, col2 HAVING COUNT() > 1;

SELECT FROM (SELECT , ROW_NUMBER() OVER (PARTITION BY col1, col2 ORDER BY id) rn FROM t) WHERE rn > 1;

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Pro Tip

Red Flag: Undefined 'duplicate' (key vs full row). Pro-Move: 'We define business key in data contract; index it for fast dup check.'

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