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Find average salary for each manager – Assume a table with manager_id and employee_salary

SQLmedium0.2 min read

SELECT manager_id, AVG(employee_salary) AS avg_salary FROM employees GROUP BY manager_id. **Why simple**: Direct aggregation. **Consider**: HAVING AVG(employee_salary) > X to filter; exclude NULL manager_id if not applicable....

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Frequency
Low
Asked at 1 company
Category
487
questions in SQL
Difficulty Split
130E|271M|86H
in this category
Total Bank
1,863
across 7 categories
Asked at these companies
Pubmatic

Why This Question Matters

This medium-level SQL question appears frequently in data engineering interviews at companies like Pubmatic. While less common, it tests deeper understanding that distinguishes strong candidates.

How to Approach This

Break this problem into components. Identify the core trade-offs involved, then walk the interviewer through your reasoning step by step. Demonstrate awareness of edge cases and production considerations - this is what separates good answers from great ones.

Expert Answer
33 words

SELECT manager_id, AVG(employee_salary) AS avg_salary FROM employees GROUP BY manager_id. Why simple: Direct aggregation. Consider: HAVING AVG(employee_salary) > X to filter; exclude NULL manager_id if not applicable. Scale: Index manager_id for large tables.

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