Reviewed by Aditya Kumar · Last reviewed 2026-08-08
To find the top 3 products sold based on total quantity, you must first aggregate the total quantity for each product and then rank or limit the results. Mechanics and "Why" The fundamental approach…
This medium-level General/Other question appears frequently in data engineering interviews at companies like Comcast. While less common, it tests deeper understanding that distinguishes strong candidates. Mastering the underlying concepts (sql) will help you answer variations of this question confidently.
Break this problem into components. Identify the core trade-offs involved, then walk the interviewer through your reasoning step by step. Demonstrate awareness of edge cases and production considerations - this is what separates good answers from great ones. The expert answer includes a code example that demonstrates the implementation pattern.
To find the top 3 products sold based on total quantity, you must first aggregate the total quantity for each product and then rank or limit the results.
The fundamental approach involves two steps: aggregation and ranking/limiting.
GROUP BY product_id (or product_name) and SUM(quantity) to calculate the total quantity sold for each unique product. This consolidates all individual sales records into a single sum per product.ORDER BY with LIMIT: The simplest method is to ORDER BY the total_quantity_sold in descending order and then use LIMIT 3. This is straightforward but doesn't gracefully handle ties if multiple products share the same quantity at the 3rd position, potentially excluding some or arbitrarily picking.RANK(), DENSE_RANK()): A more robust and often preferred method for "top N" problems is to use a window function like RANK() or DENSE_RANK(). These functions assign a rank to each product based on its total quantity. RANK() assigns the same rank to tied values and then skips the next rank(s), creating gaps (e.g., 1, 1, 3). DENSE_RANK() assigns consecutive ranks to tied values (e.g., 1, 1, 2), ensuring no gaps. For "top N" where you want to include all* items tied for the Nth spot, DENSE_RANK() is usually more appropriate. You then filter for ranks less than or equal to 3.
Using DENSE_RANK() provides a clear, tie-aware solution:
WITH ProductSales AS (
SELECT
product_id,
SUM(quantity) AS total_quantity_sold
FROM
sales_table
GROUP BY
product_id
),
RankedProductSales AS (
SELECT
product_id,
total_quantity_sold,
DENSE_RANK() OVER (ORDER BY total_quantity_sold DESC) as product_rank
FROM
ProductSales
)
SELECT
product_id,
total_quantity_sold
FROM
RankedProductSales
WHERE
product_rank <= 3
ORDER BY
product_rank, product_id;
While LIMIT is simpler, window functions are more powerful for complex ranking scenarios and handling ties. Performance-wise, both ORDER BY (for LIMIT) and window functions (which implicitly require sorting) can be resource-intensive on very large datasets. In distributed systems like Apache Spark, these operations often trigger data shuffles across nodes, which can be expensive network-wise. In cloud data warehouses like Snowflake, the query optimizer will attempt to leverage micro-partition metadata for efficient sorting, but a full sort on a massive dataset will still consume significant warehouse compute. The choice between RANK() and DENSE_RANK() depends on whether you want to skip ranks after ties or maintain consecutive ranks.
Discuss how you'd handle potential data quality issues (e.g., inconsistent product_id spellings) and the implications of data volume on query performance, referencing distributed processing concepts like shuffles or specific database optimizations.
Pro-Move: 'We use RANK when ties should share position; ROW_NUMBER when we need exactly 3 rows.'
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