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Write a query to find the top three customers by total revenue within each region.

SQLmedium0.2 min read

Reviewed by Aditya Kumar · Last reviewed 2026-03-24

SELECT * FROM (SELECT customer_id, region, SUM(revenue) AS total, RANK() OVER (PARTITION BY region ORDER BY SUM(revenue) DESC) rn FROM orders GROUP BY customer_id, region) WHERE rn <= 3. **Why**: Aggregate then rank per region. RANK or DENSE_RANK per tie rule....

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Frequency
Low
Asked at 1 company
Category
487
questions in SQL
Difficulty Split
130E|271M|86H
in this category
Total Bank
1,863
across 7 categories
Part of the SQL Query Optimization & Indexing Interview Preparation Hub
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Key Concepts Tested
partition
Expert Answer
46 words

SELECT * FROM (SELECT customer_id, region, SUM(revenue) AS total, RANK() OVER (PARTITION BY region ORDER BY SUM(revenue) DESC) rn FROM orders GROUP BY customer_id, region) WHERE rn <= 3. Why: Aggregate then rank per region. RANK or DENSE_RANK per tie rule. Scalability: Standard top-N per partition.

⚡
Pro Tip

Red Flag: RANK when exactly 3 needed—ties can yield 4+. Pro-Move: 'ROW_NUMBER for exactly 3; RANK when ties share rank.'

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