SELECT e.name AS employee_name, m.name AS manager_name FROM employees e LEFT JOIN employees m ON e.manager_id = m.id. **Why LEFT JOIN**: Include employees with no manager (CEO). For multi-level: recursive CTEs....
This medium-level SQL question appears frequently in data engineering interviews at companies like Gartner. While less common, it tests deeper understanding that distinguishes strong candidates. Mastering the underlying concepts (join) will help you answer variations of this question confidently.
Break this problem into components. Identify the core trade-offs involved, then walk the interviewer through your reasoning step by step. Demonstrate awareness of edge cases and production considerations - this is what separates good answers from great ones.
SELECT e.name AS employee_name, m.name AS manager_name FROM employees e LEFT JOIN employees m ON e.manager_id = m.id. Why LEFT JOIN: Include employees with no manager (CEO). For multi-level: recursive CTEs. Scalability: Index manager_id; handle cycles in org structure.
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Analyze My Answer β FreeAccording to DataEngPrep.tech, this is one of the most frequently asked SQL interview questions, reported at 1 company. DataEngPrep.tech maintains a curated database of 1,863+ real data engineering interview questions across 7 categories, verified by industry professionals.