**LeetCode 88:** nums1 has size m+n, m elements; nums2 has n. Merge into nums1. Fill from end (k=m+n-1) to avoid overwriting. Compare nums1[i] vs nums2[j], place larger at k.
def merge(nums1, m, nums2, n):
i, j, k = m-1, n-1, m+n-1
while j >= 0:
if i >= 0 and nums1[i] > nums2[j]:
nums1[k] = nums1[i]; i -= 1
else:
nums1[k] = nums2[j]; j -= 1
k -= 1
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