**LeetCode 88:** nums1 has size m+n, m elements; nums2 has n. Merge into nums1. Fill from end (k=m+n-1) to avoid overwriting. Compare nums1[i] vs nums2[j], place larger at k. def merge(nums1, m, nums2, n): i, j, k = m-1, n-1, m+n-1 while j >= 0: if i >= 0 and...
This easy-level Python/Coding question appears frequently in data engineering interviews at companies like Goldman Sachs. While less common, it tests deeper understanding that distinguishes strong candidates.
Start by clearly defining the core concept being asked about. Interviewers want to see that you understand the fundamentals before diving into implementation details. Structure your answer with a definition, then explain the practical application with a concise example.
LeetCode 88: nums1 has size m+n, m elements; nums2 has n. Merge into nums1. Fill from end (k=m+n-1) to avoid overwriting. Compare nums1[i] vs nums2[j], place larger at k.
def merge(nums1, m, nums2, n):
i, j, k = m-1, n-1, m+n-1
while j >= 0:
if i >= 0 and nums1[i] > nums2[j]:
nums1[k] = nums1[i]; i -= 1
else:
nums1[k] = nums2[j]; j -= 1
k -= 1
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Analyze My Answer — FreeAccording to DataEngPrep.tech, this is one of the most frequently asked Python/Coding interview questions, reported at 1 company. DataEngPrep.tech maintains a curated database of 1,863+ real data engineering interview questions across 7 categories, verified by industry professionals.