Reviewed by Aditya Kumar · Last reviewed 2026-03-24
To check if a string is a palindrome, the most robust approach involves normalizing the string (converting to lowercase and retaining only alphanumeric characters) and then comparing it to its…
Red Flag: Forgetting to handle non-alphanumeric or case. Pro-Move: 'I ask about edge cases first: empty string, unicode, case. I implement two-pointer for O(1) space and mention when string concat would be simpler.'
This medium-level Python/Coding question appears frequently in data engineering interviews at companies like Altimetrik, Infosys. While less common, it tests deeper understanding that distinguishes strong candidates. Mastering the underlying concepts (join, python) will help you answer variations of this question confidently.
Break this problem into components. Identify the core trade-offs involved, then walk the interviewer through your reasoning step by step. Demonstrate awareness of edge cases and production considerations - this is what separates good answers from great ones. The expert answer includes a code example that demonstrates the implementation pattern.
To check if a string is a palindrome, the most robust approach involves normalizing the string (converting to lowercase and retaining only alphanumeric characters) and then comparing it to its reverse. Alternatively, a more space-efficient method uses a two-pointer technique to compare characters from both ends inwards.
A string is a palindrome if it reads the same forwards and backward. For a practical check, we first need to define what constitutes "the same." This typically means ignoring case and non-alphanumeric characters (e.g., "Madam, I'm Adam" is a palindrome).
lo starting at the beginning and hi at the end of the original string. The pointers move inwards. In each step:lo is not alphanumeric, lo increments.
* If the character at hi is not alphanumeric, hi decrements.
* If both are alphanumeric, their lowercase versions are compared. If they don't match, the string is not a palindrome, and we can return False immediately (early exit).
* If they match, both pointers move inwards (lo increments, hi decrements).
This continues until lo meets or crosses hi. This method offers O(1) space complexity as it avoids creating new strings, making it superior for large text fields often encountered in data engineering contexts. Both methods have an O(N) time complexity, where N is the string length, as they must examine most characters.
The primary trade-off is between code simplicity (normalization and reverse) and space efficiency (two-pointer). For typical string lengths, the performance difference is negligible. However, when processing very large text data (e.g., cleaning user comments or document fields in a data pipeline), the two-pointer approach is preferred to avoid excessive memory allocation, which could lead to performance bottlenecks or out-of-memory errors on systems like Spark executors.
def is_palindrome_two_pointer(s: str) -> bool:
lo, hi = 0, len(s) - 1
while lo < hi:
# Skip non-alphanumeric characters from the left
while lo < hi and not s[lo].isalnum():
lo += 1
# Skip non-alphanumeric characters from the right
while lo < hi and not s[hi].isalnum():
hi -= 1
# Compare alphanumeric characters (case-insensitive)
if lo < hi and s[lo].lower() != s[hi].lower():
return False
lo += 1
hi -= 1
return True
In the interview, also mention clarifying requirements regarding case sensitivity, handling of spaces/punctuation, and the expected behavior for empty strings (usually considered palindromes) or strings with only one character (also palindromes). Discussing the space complexity implications for large datasets demonstrates an understanding of data engineering concerns.
Red Flag: Forgetting to handle non-alphanumeric or case. Pro-Move: 'I ask about edge cases first: empty string, unicode, case. I implement two-pointer for O(1) space and mention when string concat would be simpler.'
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According to DataEngPrep.tech, this is one of the most frequently asked Python/Coding interview questions, reported at 2 companies. DataEngPrep.tech maintains an editor-reviewed database of 1,863 data engineering interview questions across 7 categories.