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Home/Questions/Python/Coding/Given an n-ary tree, write code to flatten it and store the output in a list.

Given an n-ary tree, write code to flatten it and store the output in a list.

Python/Codingeasy2 min read

Reviewed by Aditya Kumar · Last reviewed 2026-03-24

Flattening an n ary tree into a list typically involves traversing the tree and collecting node values. The most common approaches are Depth First Search (DFS) or Breadth First Search (BFS), with DFS…

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Frequency
Low
Asked at 1 company
Category
179
questions in Python/Coding
Difficulty Split
127E|24M|28H
in this category
Total Bank
1,863
across 7 categories
Asked at these companies
Disney+ Hotstar

Why This Question Matters

This easy-level Python/Coding question appears frequently in data engineering interviews at companies like Disney+ Hotstar. While less common, it tests deeper understanding that distinguishes strong candidates.

How to Approach This

Start by clearly defining the core concept being asked about. Interviewers want to see that you understand the fundamentals before diving into implementation details. Structure your answer with a definition, then explain the practical application with a concise example. The expert answer includes a code example that demonstrates the implementation pattern.

Expert Answer
360 wordsIncludes code

Flattening an n-ary tree into a list typically involves traversing the tree and collecting node values. The most common approaches are Depth-First Search (DFS) or Breadth-First Search (BFS), with DFS naturally yielding a preorder traversal.

Mechanics and Why

A Depth-First Search (DFS) approach recursively explores as far as possible along each branch before backtracking. For flattening, this means visiting a node, adding its value to the result list, and then recursively calling DFS on each of its children. This inherently produces a preorder traversal, where a node is processed before any of its descendants. This is often the desired "flattened" order for representing hierarchy linearly.

def flatten_dfs(node, result_list):
    if not node:
        return
    result_list.append(node.val)
    for child in node.children:
        flatten_dfs(child, result_list)

Alternatively, a Breadth-First Search (BFS) uses an iterative approach with a queue. You add the root to the queue, then repeatedly dequeue a node, add its value to the result, and enqueue all its children. This produces a level-order traversal, which is a different flattened sequence. If a specific preorder flatten is required, DFS is generally more straightforward. The "why" behind a preorder flatten is often to represent the hierarchical structure in a linear sequence, where parent nodes appear before their children. This is useful for serialization, reconstruction, or processing tasks where the parent-child relationship needs to be preserved sequentially.

Production Considerations and Trade-offs

In a production environment, handling None nodes or empty children lists is crucial for robustness. For very deep trees, recursive DFS might hit Python's recursion depth limit, necessitating an iterative DFS implementation using an explicit stack. BFS's queue can consume significant memory for very wide trees. Both approaches have a time complexity of O(N) where N is the total number of nodes, as each node is visited once. Space complexity for DFS is O(H) (H=height) due to the call stack, while BFS is O(W) (W=maximum width) for the queue, potentially making BFS more memory-intensive for wide trees and DFS for deep trees.

In the interview, also mention whether the output list should be mutable or immutable, and consider using a generator for extremely large trees to avoid materializing the entire list in memory.

⚡
Pro Tip

Pro-Move: Iterative with stack. Red Flag: Assuming binary.

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According to DataEngPrep.tech, this is one of the most frequently asked Python/Coding interview questions, reported at 1 company. DataEngPrep.tech maintains an editor-reviewed database of 1,863 data engineering interview questions across 7 categories.

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