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Home/Questions/Python/Coding/Partitioning a Linked List based on a value

Partitioning a Linked List based on a value

Python/Codinghard0.6 min read

Reviewed by Aditya Kumar · Last reviewed 2026-03-24

**Why Partitioning:** Separates elements by predicate—foundation for quicksort on linked lists, routing (high/low priority), and stream processing (route by key). **Two-Pointer Approach:** Maintain two lists: less_than and ge_than. Single pass, O(n), O(1) extra (reuse nodes)....

🤖 Analyze Your Answer
Frequency
Low
Asked at 1 company
Category
179
questions in Python/Coding
Difficulty Split
127E|24M|28H
in this category
Total Bank
1,863
across 7 categories
Asked at these companies
Walmart
Key Concepts Tested
partitionspark

Why This Question Matters

This hard-level Python/Coding question appears frequently in data engineering interviews at companies like Walmart. While less common, it tests deeper understanding that distinguishes strong candidates. Mastering the underlying concepts (partition, spark) will help you answer variations of this question confidently.

How to Approach This

This is a senior-level question that tests architectural thinking. Lead with the high-level design, then drill into specifics. Discuss trade-offs explicitly - there is rarely one correct answer. Show awareness of scale, fault tolerance, and operational complexity.

Expert Answer
119 words

Why Partitioning: Separates elements by predicate—foundation for quicksort on linked lists, routing (high/low priority), and stream processing (route by key).

Two-Pointer Approach: Maintain two lists: less_than and ge_than. Single pass, O(n), O(1) extra (reuse nodes). Stable partition preserves relative order within each group.

Scalability: In-memory only—linked lists aren't used at big-data scale. Conceptually maps to: partitioning RDD/DataFrame by predicate, or routing events to high/low priority queues. For distributed sort: similar 'partition by range' logic in Spark.

def partition(head, x):
less = less_h = ListNode(0)
ge = ge_h = ListNode(0)
while head:
if head.val < x:
less.next = head; less = less.next
else:
ge.next = head; ge = ge.next
head = head.next
less.next = ge_h.next; ge.next = None
return less_h.next

⚡
Pro Tip

Red Flag: Creating new nodes instead of relinking. Pro-Move: 'Same pattern in our event router—partition by priority (high/low) into separate Kafka topics.'

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According to DataEngPrep.tech, this is one of the most frequently asked Python/Coding interview questions, reported at 1 company. DataEngPrep.tech maintains an editor-reviewed database of 1,863 data engineering interview questions across 7 categories.

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